Hydrochloric Acid → (Furfurylthio)acetic acid
Reaction equation
C[O:2][C:3](=[O:12])[CH2:4][S:5][CH2:6][C:7]1[O:11][CH:10]=[CH:9][CH:8]=1.[H-].[K+].Cl>CO.O>[CH2:6]([S:5][CH2:4][C:3]([OH:12])=[O:2])[C:7]1[O:11][CH:10]=[CH:9][CH:8]=1Participants
6
C[O:2][C:3](=[O:12])[CH2:4][S:5][CH2:6][C:7]1[O:11][CH:10]=[CH:9][CH:8]=1.[H-].[K+].Cl>CO.O>[CH2:6]([S:5][CH2:4][C:3]([OH:12])=[O:2])[C:7]1[O:11][CH:10]=[CH:9][CH:8]=110 g of methyl-2-(furfurylthio)acetate was dissolved in 60 ml of methanol, and the solution prepared by dissolving 4.25 g of 85% potassium hydride in 15 ml of water was added dropwise. The mixture was stirred for 2 hours at room temperature, and pH was adjusted to 5 by adding 2N aqueous hydrochloric acid. Water and methanol were evaporated under reduced pressure. 100 ml of ethyl acetate and 100 ml of water were added to the residue and extraction was carried out. The ethyl acetate layer was dried over anhydrous magnesium sulfate, and the solvent was evapoated in vacuo to obtain the captioned 2-(furfurylthio)acetic acid. Yield: 9.2 g.
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