Hydrochloric Acid → 2-(1-Methylethoxy)-5-nitrobenzoic acid
Reaction equation
[CH:1]([O:4][C:5]1[CH:14]=[CH:13][C:12]([N+:15]([O-:17])=[O:16])=[CH:11][C:6]=1[C:7]([O:9]C)=[O:8])([CH3:3])[CH3:2].[Li+].[OH-].Cl>C1COCC1.O>[CH:1]([O:4][C:5]1[CH:14]=[CH:13][C:12]([N+:15]([O-:17])=[O:16])=[CH:11][C:6]=1[C:7]([OH:9])=[O:8])([CH3:3])[CH3:2]Participants
5
Reactant 3
Product 1
Reagents, catalysts & solvents 1
Procedure
Methyl 2-isopropoxy-5-nitrobenzoate (6.92 g, 28.95 mmol) was taken up in THF/H2O (35 ml of each) and LiOH (1.39 g, 57.9 mmol) was added. The mixture was stirred at RT overnight then the pH was lowered to 1 by the addition of concentrated HCl and the product extracted in ethyl acetate (50 ml). The organic layer was dried (MgSO4) and evaporated to give 2-isopropoxy-5-nitrobenzoic acid (6.02 g, 92.5%) as a yellow solid.