Lithium Hydroxide → Phenylacetic Acid

HRID 2289129

Reaction equation

[C:1]1([CH2:7][C:8]([O-:10])=[O:9])[CH:6]=[CH:5][CH:4]=[CH:3][CH:2]=1.[Li+].[OH-]>>[C:1]1([CH2:7][C:8]([OH:10])=[O:9])[CH:6]=[CH:5][CH:4]=[CH:3][CH:2]=1

Participants

Reactant 2

HCID 3939Lithium Hydroxide

HCID 4409936Phenylacetate

Product 1

HCID 999Phenylacetic Acid

Procedure

Using the procedure in Example 2, methyl 3-chloro-4-(3-(2-phenylethyl)-7-propyl-6-benz[4,5]isoxazoloxy)propylthio)-phenylacetate was saponified with LiOH to form 3-chloro-4-(3-(2-phenylethyl)-7-propyl-6-benz[4,5]isoxazoloxy)propylthio)phenylacetic acid.

Sources & evidence

ORD record: ord-7b6ae794c25b43fe9a34253a542cd714
Source dataset: uspto-grants-2000_07
DOI: 10.6084/m9.figshare.5104873.v1
Patent number: US06090836

Linked notes

Loading…