Tetrahydrothiophene → Phenacyltetrahydrothiophenium bromide
Reaction equation
[S:1]1[CH2:5][CH2:4][CH2:3][CH2:2]1.[CH2:6]([Br:15])[C:7]([C:9]1[CH:14]=[CH:13][CH:12]=[CH:11][CH:10]=1)=[O:8]>C(#N)C>[Br-:15].[CH2:6]([S+:1]1[CH2:5][CH2:4][CH2:3][CH2:2]1)[C:7]([C:9]1[CH:14]=[CH:13][CH:12]=[CH:11][CH:10]=1)=[O:8]Participants
4
Reactant 2
Product 1
Reagents, catalysts & solvents 1
Procedure
Tetrahydrothiophene (53.2 g) was dissolved in 400 ml of acetonitrile, and thereto was slowly added a solution obtained by dissolving 100 g of phenacyl bromide in 300 ml of acetonitrile, and the solution was stirred at room temperature for 3 hours, thereby a powder was precipitated. The reaction solution was poured into 1,500 ml of ethyl acetate, and the powder was filtered out and dried, thus 137 g of phenacyltetrahydrothiophenium bromide was obtained.