Methyl iodide → 2-Chloro-3-methoxybenzaldehyde
Reaction equation
[Cl:1][C:2]1[C:9]([OH:10])=[CH:8][CH:7]=[CH:6][C:3]=1[CH:4]=[O:5].[C:11]([O-])([O-])=O.[K+].[K+].CI>CN(C=O)C>[Cl:1][C:2]1[C:9]([O:10][CH3:11])=[CH:8][CH:7]=[CH:6][C:3]=1[CH:4]=[O:5]Participants
5
Reactant 3
Product 1
Reagents, catalysts & solvents 1
Procedure
To a solution of 2-chloro-3-hydroxybenzaldehyde (4.55 g, 29 mmol) in DMF (30 mL) was added K2CO3 (4.8 g, 34.9 mmol) followed by MeI (2.7 mL, 43.6 mmol), and the mixture was stirred at room temperature for 16 hours. Following concentration in vacuo, the residual was taken up in ethyl acetate, washed with H2O, brine, dried over Na2SO4, and concentrated. Purification by column chromatography on silica gel with ethyl acetate/hexanes 1/5 afforded 2-chloro-3-methoxybenzaldehyde 7a (4.68 g, 94%) as a colorless oil, which solidified upon standing. GCMS (EI) m/z 170, 172 (M+).