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Water → 3-Bromo-4-phenoxybenzaldehyde

HRID 416174
Notes
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Reaction equation

HRID 416174 reaction equation
[Br:1][C:2]1[CH:3]=[C:4]([CH:7]=[CH:8][C:9]=1F)[CH:5]=[O:6].[C:11]1([OH:17])[CH:16]=[CH:15][CH:14]=[CH:13][CH:12]=1.C(=O)([O-])[O-].[K+].[K+].O>CN(C)C=O>[Br:1][C:2]1[CH:3]=[C:4]([CH:7]=[CH:8][C:9]=1[O:17][C:11]1[CH:16]=[CH:15][CH:14]=[CH:13][CH:12]=1)[CH:5]=[O:6]
ParticipantsConditionsProcedureWorkupSources & evidenceReaction notes

Participants

6

Reactant 4

HCID 962WaterHCID 996PhenolHCID 11430Potassium CarbonateHCID 1736043-Bromo-4-fluorobenzaldehyde

Product 1

HCID 593425893-Bromo-4-phenoxybenzaldehydeYield 82%

Reagents, catalysts & solvents 1

HCID 6228Dimethylformamide
Solvent

Conditions

Temperature
90 °C

Procedure

To a solution of 3-bromo-4-fluorobenzaldehyde (2.03 g, 10.0 mmol) and phenol (0.941 g, 10.0 mmol) in N,N-dimethylformamide (10 mL) was added potassium carbonate (1.66 g, 12.0 mmol), and the mixture was stirred at 90° C. for 16 hr under nitrogen atmosphere. Water was added to the reaction mixture, and the mixture was extracted with ethyl acetate. The extract was washed with saturated brine, dried over anhydrous magnesium sulfate, and concentrated under reduced pressure. The residue was purified by silica gel column chromatography (ethyl acetate:hexane=0:100-15:85) to give the title compound (2.27 g, yield 82%) as a pale-yellow oil.

Workup

  1. extractionthe mixture was extracted with ethyl acetate
  2. washThe extract was washed with saturated brine
  3. dry with materialdried over anhydrous magnesium sulfate
  4. concentrationconcentrated under reduced pressure
  5. customThe residue was purified by silica gel column chromatography (ethyl acetate:hexane=0:100-15:85)

Sources & evidence

ORD record
ord-f56fb49e9ec04b64bd9276e62b2e9b7a
Source dataset
uspto-grants-2012_01
DOI
10.6084/m9.figshare.5104873.v1
Patent number
US08088821B2

Reaction notes

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On this pageParticipantsConditionsProcedureWorkupSources & evidenceReaction notes