Sodium Iodide → 8-(4-(Methoxycarbonyl)benzyloxy)naphthalene-2-sulfonic acid
Reaction equation
[OH:1][C:2]1[CH:3]=[CH:4][CH:5]=[C:6]2[C:11]=1[CH:10]=[C:9]([S:12]([OH:15])(=[O:14])=[O:13])[CH:8]=[CH:7]2.[OH-].[K+].Br[CH2:19][C:20]1[CH:29]=[CH:28][C:23]([C:24]([O:26][CH3:27])=[O:25])=[CH:22][CH:21]=1.[Na+].[I-]>CN(C=O)C.O>[CH3:27][O:26][C:24]([C:23]1[CH:28]=[CH:29][C:20]([CH2:19][O:1][C:2]2[CH:3]=[CH:4][CH:5]=[C:6]3[C:11]=2[CH:10]=[C:9]([S:12]([OH:15])(=[O:13])=[O:14])[CH:8]=[CH:7]3)=[CH:21][CH:22]=1)=[O:25]Participants
7
