Catechol → Guaiacol
Reaction equation
[C:1]1([C:3](=[CH:5][CH:6]=[CH:7][CH:8]=1)[OH:4])[OH:2].[CH3:9]O>>[C:1]1([OH:2])[CH:3]=[CH:5][CH:6]=[CH:7][CH:8]=1.[C:3]1([O:4][CH3:9])[C:1](=[CH:8][CH:7]=[CH:6][CH:5]=1)[OH:2]Participants
4
Reactant 2
Product 2
Procedure
When the temperature of the catalyst stratum reached 280° C., a starting compound mixture consisting of catechol and methyl alcohol in a molar mixing ratio of 1:3.44 was evaporated in a evaporator, and the resultant starting compound mixture gas was fed in a feeding rate of 10.5 g/min. together with a nitrogen gas into the reaction tube for 14 hours, to etherify catechol with methyl alcohol and to produce a dihydric phenol compound monoalkylether, i.e., guaiacol. The reaction mixture gas discharged from the reaction tube was cooled to a temperature of 40° C. The resultant liquefied product was collected from the reaction mixture.
Workup
- customreached 280° C.
- customwas evaporated in a evaporator