2-Naphthol → beta-Carbaryl
Reaction equation
[CH:1]1[C:10]2[C:5](=[CH:6][CH:7]=[CH:8][CH:9]=2)[CH:4]=[CH:3][C:2]=1[OH:11].[CH3:12][NH:13][C:14](Cl)=[O:15]>C(C1C=CC=CC=1)(C)(C)C>[CH:1]1[C:10]2[C:5](=[CH:6][CH:7]=[CH:8][CH:9]=2)[CH:4]=[CH:3][C:2]=1[O:11][C:14](=[O:15])[NH:13][CH3:12]Participants
4
Reactant 2
Product 1
Reagents, catalysts & solvents 1
Conditions
- Temperature
- 0 °C
Procedure
72 parts by weight of β-naphthol are dissolved in 250 parts by weight of t-butylbenzene at 80° C. 46.7 parts by weight of methylcarbamyl chloride are passed into this solution over a period of 10 minutes while nitrogen is simultaneously bubbled through the solution. The reaction is complete after 15 minutes. The hot reaction solution is then cooled to 0° C. 83.5 parts by weight of β-naphthyl-N-methylcarbamate are precipitated, this being equivalent to a yield of 83% of theory. The melting point is 119° C.