Methanol → HCID 59615459、化合物

HRID 43585ノート

反応式

HRID 43585 の反応式
[Cl:1][C:2]1[N:3]=[C:4]([C:9]([NH:11][C:12]2[CH:17]=[CH:16][C:15]([C:18]3[O:19][C:20]([CH2:28][CH3:29])=[C:21]([C:23]([O:25]CC)=[O:24])[N:22]=3)=[CH:14][CH:13]=2)=[O:10])[NH:5][C:6]=1[CH2:7][CH3:8].[OH-].[Li+].CO>O1CCCC1>[Cl:1][C:2]1[N:3]=[C:4]([C:9]([NH:11][C:12]2[CH:17]=[CH:16][C:15]([C:18]3[O:19][C:20]([CH2:28][CH3:29])=[C:21]([C:23]([OH:25])=[O:24])[N:22]=3)=[CH:14][CH:13]=2)=[O:10])[NH:5][C:6]=1[CH2:7][CH3:8]

参加物

5

反応物 3

HCID 887MethanolHCID 3939Lithium HydroxideHCID 67548256Ethyl 2-(4-{[(4-chloro-5-ethyl-1H-imidazol-2-yl)carbonyl]amino}phenyl)-5-ethyl-1,3-oxazole-4-carboxylate

生成物 1

HCID 59615459HCID 59615459、化合物収率 87%

試薬・触媒・溶媒 1

HCID 8028Tetrahydrofuran溶媒

実験手順

The same operation as in Example (91d) was performed using ethyl 2-(4-{[(4-chloro-5-ethyl-1H-imidazol-2-yl)carbonyl]amino}phenyl)-5-ethyl-1,3-oxazole-4-carboxylate obtained in Example (99c) (0.12 g, 2.88 mmol), 2 N lithium hydroxide (2 mL, 4 mmol), methanol (2 mL) and tetrahydrofuran (5 mL), to obtain 97 mg of the title compound as a light pink solid (87%).

出典と根拠

ORDレコード
ord-47c37a86afec48b4b740271b8f3b501b
出典データセット
uspto-grants-2013_09
特許番号
US08536197B2

反応ノート

読み込み中…