Methanol → 2-(4-{[(4-Chloro-5-ethyl-1H-imidazol-2-yl)carbonyl]amino}-3-methoxyphenyl)-5-methyl-1,3-oxazole-4-carboxylic acid

HRID 43614ノート

反応式

HRID 43614 の反応式
[Cl:1][C:2]1[N:3]=[C:4]([C:9]([NH:11][C:12]2[CH:17]=[CH:16][C:15]([C:18]3[O:19][C:20]([CH3:27])=[C:21]([C:23]([O:25]C)=[O:24])[N:22]=3)=[CH:14][C:13]=2[O:28][CH3:29])=[O:10])[NH:5][C:6]=1[CH2:7][CH3:8].[OH-].[Li+].CO>O1CCCC1>[Cl:1][C:2]1[N:3]=[C:4]([C:9]([NH:11][C:12]2[CH:17]=[CH:16][C:15]([C:18]3[O:19][C:20]([CH3:27])=[C:21]([C:23]([OH:25])=[O:24])[N:22]=3)=[CH:14][C:13]=2[O:28][CH3:29])=[O:10])[NH:5][C:6]=1[CH2:7][CH3:8]

参加物

5

反応物 3

HCID 887MethanolHCID 3939Lithium HydroxideHCID 67549048HCID 67549048、化合物

生成物 1

HCID 601358282-(4-{[(4-Chloro-5-ethyl-1H-imidazol-2-yl)carbonyl]amino}-3-methoxyphenyl)-5-methyl-1,3-oxazole-4-carboxylic acid収率 87%

試薬・触媒・溶媒 1

HCID 8028Tetrahydrofuran溶媒

実験手順

The same operation as in Example (91d) was performed using methyl 2-(4-{[(4-chloro-5-ethyl-1H-imidazol-2-yl)carbonyl]amino}-3-methoxyphenyl)-5-methyl-1,3-oxazole-4-carboxylate obtained in Example (102e) (90 mg, 0.21 mmol), 2 N lithium hydroxide (3 mL, 6 mmol), methanol (3 mL) and tetrahydrofuran (3 mL), to obtain 74 mg of the title compound as a light pink solid (85%).

出典と根拠

ORDレコード
ord-a0c4539f85a148df882255cabac61199
出典データセット
uspto-grants-2013_09
特許番号
US08536197B2

反応ノート

読み込み中…