Sodium Hydroxide → HCID 19091325、化合物
反応式
[OH-].[Na+].C([O:5][C:6](=[O:31])[CH:7]([CH2:19][C:20]1[CH:25]=[CH:24][CH:23]=[C:22]([NH:26][S:27]([CH3:30])(=[O:29])=[O:28])[CH:21]=1)[NH:8][C:9]([O:11][CH2:12][C:13]1[CH:18]=[CH:17][CH:16]=[CH:15][CH:14]=1)=[O:10])C>C1COCC1>[CH2:12]([O:11][C:9]([NH:8][CH:7]([C:6]([OH:31])=[O:5])[CH2:19][C:20]1[CH:25]=[CH:24][CH:23]=[C:22]([NH:26][S:27]([CH3:30])(=[O:29])=[O:28])[CH:21]=1)=[O:10])[C:13]1[CH:18]=[CH:17][CH:16]=[CH:15][CH:14]=1参加物
4
実験手順
Add 1N NaOH (107 mL) to the product of Step A (14.80 g) in THF (100 mL) and stir overnight. Concentrate the THF solution in vacuo and partition between EtOAc (700 mL)/2N HCl (200 mL). Concentrate the dried (MgSO4) EtOAc solution in vacuo to a residue. Add CH2Cl2 (50 mL) and concentrate in vacuo (3 times) to give N-benzyloxycarbonyl-3-methanesulfonamido-D,L-phenylalanine.
後処理
- concentrationConcentrate the THF solution in vacuo
- custompartition between EtOAc (700 mL)/2N HCl (200 mL)
- concentrationConcentrate the
- dry with materialdried (MgSO4) EtOAc solution in vacuo to a residue
- concentrationAdd CH2Cl2 (50 mL) and concentrate in vacuo (3 times)
出典と根拠
- ORDレコード
- ord-6ef29506c8b346bfad1dcdec32b89d06
- 出典データセット
- uspto-grants-1994_03
- 特許番号
- US05298492
反応ノート
読み込み中…