Sodium hydride → HCID 178462379、化合物

HRID 60536ノート

反応式

HRID 60536 の反応式
[H-].[Na+].[BH4-].[Na+].O.[NH2:6][C:7]1[N:12]=[C:11]([SH:13])[N:10]=[C:9]([OH:14])[CH:8]=1.Cl[C@@H:16]([C:18]1[CH:23]=[CH:22][CH:21]=[CH:20][C:19]=1[F:24])[CH3:17]>CN(C=O)C>[NH2:6][C:7]1[N:12]=[C:11]([S:13][C@H:16]([C:18]2[CH:23]=[CH:22][CH:21]=[CH:20][C:19]=2[F:24])[CH3:17])[N:10]=[C:9]([OH:14])[CH:8]=1

参加物

6

実験手順

NaH (60% in oil, 1.05 g, 26.3 mmol) was added in portions followed by NaBH4 (0.099 g, 2.7 mmol) to 6-amino-2-mercaptopyrimidin-4-ol monohydrate (4.23 g, 26.3 mmol) in DMF (40 mL). After 30 minutes, 1-[(1R)-1-chloroethyl]-2-fluorobenzene (5.0 g, 31.5 mmol) in DMF (10 mL) was added and the reaction mixture was stirred for 24 h. The reaction mixture was concentrated and partitioned between water and DCM, the organic phase was dried (MgSO4) and evaporated. The residue was purified by flash column chromatography (a stepwise gradient of 5-10% MeOH in CHCl3) to give the title compound (5.20 g, 75% yield).

後処理

  1. concentrationThe reaction mixture was concentrated
  2. custompartitioned between water and DCM
  3. dry with materialthe organic phase was dried (MgSO4)
  4. customevaporated
  5. customThe residue was purified by flash column chromatography (a stepwise gradient of 5-10% MeOH in CHCl3)

出典と根拠

ORDレコード
ord-dffca4060c9b4372a3edffb642c3f6b7
出典データセット
uspto-grants-2016_09
特許番号
US09440992B2

反応ノート

読み込み中…