Sodium Hydroxide → HCID 89501036、化合物
反応式
[Cl:1][C:2]1[C:3]([F:19])=[CH:4][C:5]([N:14]2[CH:18]=[N:17][N:16]=[N:15]2)=[C:6](/[CH:8]=[CH:9]/[C:10]([O:12]C)=[O:11])[CH:7]=1.[OH-].[Na+]>CO.C1COCC1>[Cl:1][C:2]1[C:3]([F:19])=[CH:4][C:5]([N:14]2[CH:18]=[N:17][N:16]=[N:15]2)=[C:6](/[CH:8]=[CH:9]/[C:10]([OH:12])=[O:11])[CH:7]=1参加物
5
実験手順
To Intermediate 5C (5 g, 17.7 mmol) in MeOH (50 mL) and THF (25 mL) was added 10% NaOH solution (25 mL). After 2 h, the reaction was concentrated and the residue was diluted with H2O. The pH was adjusted to 2 to 3 with 1.5N HCl and the resultant solid was filtered and washed with petroleum ether to afford 2 g of Intermediate 5. MS (ESI) m/z: 269.0 (M+H)+.
後処理
- concentrationthe reaction was concentrated
- additionthe residue was diluted with H2O
- filtrationthe resultant solid was filtered
- washwashed with petroleum ether
出典と根拠
- ORDレコード
- ord-58352e6959fe425e8a5c8fab64eefc8a
- 出典データセット
- uspto-grants-2016_09
- 特許番号
- US09447110B2
反応ノート
読み込み中…