Pentachloropyridine → 2,3,5,6-Tetrachloropyridine

반응식

[Cl:1][C:2]1[N:7]=[C:6]([Cl:8])[C:5]([Cl:9])=[C:4](Cl)[C:3]=1[Cl:11].P([O-])([O-])(O)=O.[NH4+].[NH4+]>[Zn]>[Cl:8][C:6]1[C:5]([Cl:9])=[CH:4][C:3]([Cl:11])=[C:2]([Cl:1])[N:7]=1

참가 물질

실험 절차

On reaction of 12.76 g (0.05 mol) of pentachloropyridine with 4.1 g (0.063 gram atom) of zinc dust and 10.6 g (0.08 mol) of diammonium hydrogen phosphate using the method described in Example 1, there is obtained 10.2 g (93% of theory) of crude 2,3,5,6-tetrachloropyridine, which contains, according to gas-chromatographical analysis, 95.1% of 2,3,5,6-tetrachloropyridine, 0.8% of 2,3,5-trichloropyridine, 0.5% of 2,3,6-trichloropyridine and 3.6% of pentachloropyridine.