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2,6-Lutidine → HCID 21093748, 화합물

HRID 1349941
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HRID 1349941 반응식
N1C(C)=CC=CC=1C.[Br:9][C:10]1[CH:11]=[C:12]([N+:20]([O-:22])=[O:21])[C:13]([O:18][CH3:19])=[C:14]([CH:17]=1)[CH2:15]O.[Br-:23].[Li+].CS(OS(C)(=O)=O)(=O)=O>O1CCCC1>[Br:9][C:10]1[CH:11]=[C:12]([N+:20]([O-:22])=[O:21])[C:13]([O:18][CH3:19])=[C:14]([CH:17]=1)[CH2:15][Br:23]
참가 물질실험 절차후처리출처 및 근거반응 노트

참가 물질

6

반응물 4

HCID 79372,6-LutidineHCID 81560Methanesulfonic anhydrideHCID 82050Lithium BromideHCID 69353261HCID 69353261, 화합물

생성물 1

HCID 21093748HCID 21093748, 화합물수율 118.6%

시약·촉매·용매 1

HCID 8028Tetrahydrofuran용매2회

실험 절차

2,6-Lutidine (10.5 mL) was added to a stirring solution of 5-bromo-2-methoxy-3-nitrobenzyl alcohol (13.6 g) and lithium bromide (11.75 g) in anhydrous tetrahydrofuran (200 mL) at 0° C. A solution of methanesulfonic anhydride (11.8 g) in anhydrous tetrahydrofuran (20 mL) was added dropwise. The resulting mixture was left to stir at room temperature for 16 h. It was partitioned between diethyl ether (250 mL) and saturated sodium hydrogen carbonate (150 mL). The organic layer was dried (sodium sulfate) and evaporated in vacuo. Silica gel chromatography of the crude residue eluting with diethyl ether in petroleum ether gave the title compound (20 g) as an amber oil.

후처리

  1. waitThe resulting mixture was left
  2. customIt was partitioned between diethyl ether (250 mL) and saturated sodium hydrogen carbonate (150 mL)
  3. dry with materialThe organic layer was dried (sodium sulfate)
  4. customevaporated in vacuo
  5. washSilica gel chromatography of the crude residue eluting with diethyl ether in petroleum ether

출처 및 근거

ORD 기록
ord-002ff63b7cbe4c9483a2082252a1066f
출처 데이터셋
uspto-grants-2007_05
DOI
10.6084/m9.figshare.5104873.v1
특허 번호
US07214674B2

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