[Cl:1][C:2]1[CH:10]=[C:9]2[C:5]([CH:6]=[C:7]([C:11]([O:13][CH2:14][CH3:15])=[O:12])[NH:8]2)=[CH:4][CH:3]=1.[H-].[Na+].I[CH3:19]>>[Cl:1][C:2]1[CH:10]=[C:9]2[C:5]([CH:6]=[C:7]([C:11]([O:13][CH2:14][CH3:15])=[O:12])[N:8]2[CH3:19])=[CH:4][CH:3]=1The preparation is carried out as in Example 1.1, from 8.0 g (35.8 mmol) of ethyl 6-chloro-1H-indole-2-carboxylate, from 1.8 g of 60% sodium hydride and from 2.8 ml of iodomethane.
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