Hydrochloric Acid → 4-(1-Ethoxyethyl)benzoic acid

HRID 1479733노트

반응식

HRID 1479733 반응식
[CH2:1]([O:3][CH:4]([C:6]1[CH:15]=[CH:14][C:9]([C:10]([O:12]C)=[O:11])=[CH:8][CH:7]=1)[CH3:5])[CH3:2].[OH-].[Li+].Cl>CO.O>[CH2:1]([O:3][CH:4]([C:6]1[CH:7]=[CH:8][C:9]([C:10]([OH:12])=[O:11])=[CH:14][CH:15]=1)[CH3:5])[CH3:2]

참가 물질

6

반응물 3

HCID 313Hydrochloric AcidHCID 3939Lithium HydroxideHCID 89580551Methyl 4-(1-ethoxyethyl)benzoate

생성물 1

HCID 189137424-(1-Ethoxyethyl)benzoic acid수율 93.5%

시약·촉매·용매 2

HCID 887Methanol용매HCID 962Water용매

실험 절차

To the solution of methyl 4-(1-ethoxyethyl)benzoate (191 mg, 0.92 mmol) in methanol and water (50 mL/10 mL) was added lithium hydroxide (100 mg, 4.2 mmol), the solution was stirred at room temperature for 12 hours. Then the solution was acidified by hydrogen chloride (1 N/mol) pH to 6, extracted with dichloromethane (80 mL*3), evaporated the solvent to give 4-(1-ethoxyethyl)benzoic acid (167 mg, 93%).

후처리

  1. extractionto 6, extracted with dichloromethane (80 mL*3)
  2. customevaporated the solvent

출처 및 근거

ORD 기록
ord-38e77086adac4dc5b9b113e71af7f564
출처 데이터셋
uspto-grants-2016_08
특허 번호
US09409865B2

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