Hydrochloric Acid → Sodium hydroxide rebamipide
반응식
Cl.[OH-].[Na+:3].[CH:4]1[CH:5]=[CH:6][C:7]2[NH:14][C:12](=[O:13])[CH:11]=[C:10]([CH2:15][CH:16]([NH:20][C:21]([C:23]3[CH:24]=[CH:25][C:26]([Cl:29])=[CH:27][CH:28]=3)=[O:22])[C:17]([OH:19])=[O:18])[C:8]=2[CH:9]=1>O>[OH-:13].[Na+:3].[CH:4]1[CH:5]=[CH:6][C:7]2[NH:14][C:12](=[O:13])[CH:11]=[C:10]([CH2:15][CH:16]([NH:20][C:21]([C:23]3[CH:28]=[CH:27][C:26]([Cl:29])=[CH:25][CH:24]=3)=[O:22])[C:17]([OH:19])=[O:18])[C:8]=2[CH:9]=1참가 물질
5
실험 절차
373 ML of 10 N hydrochloric acid (440 g, 3.73 mol) and 14.8 L of an aqueous solution containing 4% (w/v) HPMC (TC-5E) were mixed to prepare a hydrochloric acid-HPMC ITC-5E) solution. To 14 L of an aqueous solution of sodium hydroxide which was prepared by adding purified water to 134 g of sodium hydroxide (3.35 mol), 600 g of rebamipide (1.62 mol) was added and dissolved with heating to give a sodium hydroxide-rebamipide solution.