Hydrochloric Acid → N-Ethyl-3,6-carbazolediol

반응식

O.[OH-].[Na+].C([O:7][C:8]1[CH:9]=[CH:10][C:11]2[N:12]([CH2:25][CH3:26])[C:13]3[C:18]([C:19]=2[CH:20]=1)=[CH:17][C:16]([O:21]C(=O)C)=[CH:15][CH:14]=3)(=O)C.Cl>>[CH2:25]([N:12]1[C:13]2[CH:14]=[CH:15][C:16]([OH:21])=[CH:17][C:18]=2[C:19]2[C:11]1=[CH:10][CH:9]=[C:8]([OH:7])[CH:20]=2)[CH3:26]

참가 물질

반응물 4

HCID 313Hydrochloric Acid

HCID 962Water

HCID 14798Sodium Hydroxide

HCID 12331788N-ethyl-3,6-carbazolediol diacetate

생성물 1

HCID 21419583N-Ethyl-3,6-carbazolediol

실험 절차

To 700 ml of water containing 80 g (2.0 mole) of sodium hydroxide was added 85 g (0.27 mole) of N-ethyl-3,6-carbazolediol diacetate. The reaction mixture was heated for one hour then acidified with 3N hydrochloric acid to give the product which was recrystallized from ethanolwater. M.P. 190°-200°C (dec.).