Hydrochloric Acid → p-Tert-octylphenol phenol formaldehyde
반응식
[C:1]([C:9]1[CH:14]=[CH:13][C:12]([OH:15])=[CH:11][CH:10]=1)([CH2:4][C:5]([CH3:8])([CH3:7])[CH3:6])([CH3:3])[CH3:2].[C:16]1([OH:22])[CH:21]=[CH:20][CH:19]=[CH:18][CH:17]=1.[CH2:23]=[O:24].Cl>>[C:1]([C:9]1[CH:10]=[CH:11][C:12]([OH:15])=[CH:13][CH:14]=1)([CH2:4][C:5]([CH3:8])([CH3:7])[CH3:6])([CH3:2])[CH3:3].[C:16]1([OH:22])[CH:21]=[CH:20][CH:19]=[CH:18][CH:17]=1.[CH2:23]=[O:24]참가 물질
5
반응 조건
- 온도
- 160 °C
실험 절차
206 g (1 mole) of p-tert-octylphenol, 60 g (0.64 mole) of phenol, 121.0 g (1.5 moles) of 37% formalin and 1.5 g of 35% HCl were condensed under water reflux for 10 hours. The reaction mixture was dehydrated by heating it to 160° C. under atmospheric pressure and then under reduced pressure to give a pale yellow p-tert-octylphenol/phenol/formaldehyde co-condensate having a softening point of 102° C.