Methyl iodide → HCID 59639574, 화합물

HRID 2250044노트

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HRID 2250044 반응식
[F:1][C:2]1[CH:7]=[CH:6][CH:5]=[CH:4][C:3]=1[C:8]1[C:9]2[CH:19]=[CH:18][C:17](=[O:20])[NH:16][C:10]=2[N:11]=[C:12]([S:14][CH3:15])[N:13]=1.[H-].[Na+].I[CH3:24]>C1COCC1>[F:1][C:2]1[CH:7]=[CH:6][CH:5]=[CH:4][C:3]=1[C:8]1[C:9]2[CH:19]=[CH:18][C:17](=[O:20])[N:16]([CH3:24])[C:10]=2[N:11]=[C:12]([S:14][CH3:15])[N:13]=1

참가 물질

5

반응물 3

HCID 6328Methyl iodideHCID 24758Sodium hydrideHCID 59639533HCID 59639533, 화합물

생성물 1

HCID 59639574HCID 59639574, 화합물수율 92%

시약·촉매·용매 1

HCID 8028Tetrahydrofuran용매

실험 절차

To a solution of 4-(2-fluoro-phenyl)-2-methylsulfanyl-8H-pyrido[2,3-d]pyrimidin-7-one (120 mg, 0.42 mmol) in 20 mL of anhyd THF was added NaH (50 mg, 1.2 mmol, 60% dispersion in mineral oil, 3 eq) followed by iodomethane (74 μL, 1.2 mmol, 3 eq). The reaction mixture was stirred 1 h at 23°, quenched with saturated aq NH4Cl. (20 mL), Et2O (100 mL) was added and the layers were separated. The organic layer was washed with satd aq NaCl, dried (MgSO4), filtered and evaporated. The yellow residue was then purified by Flash chromatography to afford 100 mg (92% yield) of 4-(2-Fluoro-phenyl)-8-methyl-2-methylsulfanyl-8H-pyrido[2,3-d]pyrimidin-7-one. 1H-NMR δ 2.68 (s, 3H), 3.81 (s, 3H), 6.61 (d, 1H, J=9.8 Hz), 7.22 (m, 3H), 7.50 (m, 3H). LC MS (m/e)=302 (MH+). Rt=2.17 min.

후처리

  1. customquenched with saturated aq NH4Cl
  2. addition(20 mL), Et2O (100 mL) was added
  3. customthe layers were separated
  4. washThe organic layer was washed with satd aq NaCl
  5. dry with materialdried (MgSO4)
  6. filtrationfiltered
  7. customevaporated
  8. customThe yellow residue was then purified by Flash chromatography

출처 및 근거

ORD 기록
ord-5e8ffd0fc0234c2ea95097d0fe5fc7d1
출처 데이터셋
uspto-grants-2008_01
특허 번호
US07314934B2

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