반응식
[CH3:1][C@@H:2]1[N:23]2[C:6]3[C:7]([C:19]([C:21]([C:24]([OH:26])=[O:25])=[CH:22]2)=[O:20])=[CH:8][C:9]([F:18])=[C:10]([N:11]2[CH2:16][CH2:15][N:14]([CH3:17])[CH2:13][CH2:12]2)[C:5]=3[O:4][CH2:3]1>CCC(C)=O>[CH3:1][C@@H:2]1[N:23]2[CH:22]=[C:21]([C:24]([OH:26])=[O:25])[C:19]([C:7]3=[CH:8][C:9]([F:18])=[C:10]([N:11]4[CH2:16][CH2:15][N:14]([CH3:17])[CH2:13][CH2:12]4)[C:5](=[C:6]23)[O:4][CH2:3]1)=[O:20].[CH3:1][C@@H:2]1[N:23]2[CH:22]=[C:21]([C:24]([OH:26])=[O:25])[C:19]([C:7]3=[CH:8][C:9]([F:18])=[C:10]([N:11]4[CH2:16][CH2:15][N:14]([CH3:17])[CH2:13][CH2:12]4)[C:5](=[C:6]23)[O:4][CH2:3]1)=[O:20].[OH2:4]참가 물질
3
반응 조건
- 온도
- -5 °C
실험 절차
1.5 g of levofloxacin crude was put in suspension in 15 ml of MEK. The mixture was heated to reflux temperature until complete dissolution of the material. Then the solution was cooled to −5° C. over a period of 3 hours. The precipitate was filtrated under vacuum, washed with 1.5 ml of MEK and dried at 30° C. in a vacuum oven to give 840 mg (84%) of purified levofloxacin hemihydrate.
후처리
- temperatureThe mixture was heated
- temperatureto reflux temperature
- dissolutionuntil complete dissolution of the material
- filtrationThe precipitate was filtrated under vacuum
- washwashed with 1.5 ml of MEK
- customdried at 30° C. in a vacuum oven
출처 및 근거
- ORD 기록
- ord-5ef30b4014b14c6b9ef8a9cf7daa197a
- 출처 데이터셋
- uspto-grants-2008_09
- 특허 번호
- US07425628B2
연결된 노트
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