Sodium Iodide → 3-Hydroxy-4-iodobenzoic acid
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[OH-].[Na+].[I-:3].[Na+].[OH:5][C:6]1[CH:7]=[C:8]([CH:12]=[CH:13][CH:14]=1)[C:9]([OH:11])=[O:10].Cl[O-].[Na+]>CO>[OH:5][C:6]1[CH:7]=[C:8]([CH:12]=[CH:13][C:14]=1[I:3])[C:9]([OH:11])=[O:10][OH-].[Na+].[I-:3].[Na+].[OH:5][C:6]1[CH:7]=[C:8]([CH:12]=[CH:13][CH:14]=1)[C:9]([OH:11])=[O:10].Cl[O-].[Na+]>CO>[OH:5][C:6]1[CH:7]=[C:8]([CH:12]=[CH:13][C:14]=1[I:3])[C:9]([OH:11])=[O:10]21 g (520 mmol) of sodium hydroxide and then 78.7 g (520 mmol) of sodium iodide are added to a solution of 69 g (500 mmol) of 3-hydroxybenzoic acid in 700 mL of methanol. The reaction mixture is cooled to 0° C. and aqueous sodium hypochlorite solution is then added (520 mmol). The reaction medium is stirred at 0-5° C. for 2 hours and then at room temperature overnight. The methanol is evaporated off and the reaction medium is then acidified with concentrated hydrochloric acid solution. The precipitated product is filtered off, washed with water and dried. 41.92 g of 3-hydroxy-4-iodobenzoic acid are obtained in the form of an off-white solid. The aqueous phase is extracted with ethyl acetate, dried over magnesium sulfate, filtered and evaporated and the residue obtained is taken up in heptane and then filtered.
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