[CH2:1]([O:3][C:4]1[CH:5]=[C:6]2[C:11](=[C:12]([N+:14]([O-])=O)[CH:13]=1)[N:10]=[CH:9][CH:8]=[CH:7]2)[CH3:2].[Sn](Cl)Cl>Cl>[CH2:1]([O:3][C:4]1[CH:5]=[C:6]2[C:11](=[C:12]([NH2:14])[CH:13]=1)[N:10]=[CH:9][CH:8]=[CH:7]2)[CH3:2]In a similar fashion using route 1 general procedure 4, 6-ethoxy-8-nitroquinoline (Intermediate 35) (900 mg, 4.12 mmol), tin (II) chloride (2.4 g, 12.4 mmol) and 6 N HCl (10 drops) gave the title compound (700 mg, 90%) which was used in the next step without purification.
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