Stannous Chloride → 6-Fluoroquinolin-8-amine

HRID 513400노트

반응식

HRID 513400 반응식
[F:1][C:2]1[CH:3]=[C:4]2[C:9](=[C:10]([N+:12]([O-])=O)[CH:11]=1)[N:8]=[CH:7][CH:6]=[CH:5]2.[Sn](Cl)Cl>Cl>[F:1][C:2]1[CH:3]=[C:4]2[C:9](=[C:10]([NH2:12])[CH:11]=1)[N:8]=[CH:7][CH:6]=[CH:5]2

참가 물질

4

반응물 2

HCID 24479Stannous ChlorideHCID 154273Quinoline, 6-fluoro-8-nitro-2회

생성물 1

HCID 132279926-Fluoroquinolin-8-amine수율 74.1%

시약·촉매·용매 1

HCID 313Hydrochloric Acid촉매

실험 절차

In a similar fashion using route 1 general procedure 4, 6-fluoro-8-nitroquinoline (Intermediate 36) (1.0 g, 5.41 mmol), tin (II) chloride (3.08 g, 16.2 mmol) and 6N HCl (5 drops) gave the title compound (650 mg, 74%) which was used in the next step without further purification.

출처 및 근거

ORD 기록
ord-c5a649fabcfb4a2fbff7a40b2275815b
출처 데이터셋
uspto-grants-2015_08
특허 번호
US09102688B2

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