Hydrochloric Acid → (4-Methoxy-6-Methyl-2-pyriMidinyl)thiourea, 97+%

HRID 579904노트

반응식

HRID 579904 반응식
[CH3:1][O:2][C:3]1[CH:8]=[C:7]([CH3:9])[N:6]=[C:5]([NH:10][C:11]([NH:13]NC(=O)C2C=CC=CC=2)=[S:12])[N:4]=1.[OH-].[Na+].Cl>>[CH3:1][O:2][C:3]1[CH:8]=[C:7]([CH3:9])[N:6]=[C:5]([NH:10][C:11]([NH2:13])=[S:12])[N:4]=1

참가 물질

4

반응물 3

HCID 313Hydrochloric AcidHCID 14798Sodium HydroxideHCID 54321636HCID 54321636, 화합물

생성물 1

HCID 939981(4-Methoxy-6-Methyl-2-pyriMidinyl)thiourea, 97+%수율 102.5%

실험 절차

A mixture of 25 g of the compound from Example 3 and 55 ml of 10% aqueous sodium hydroxide was heated on the steam bath for 30 minutes, cooled, neutralized with aqueous HCl to pH 8, filtered, washed with water, dried by suction, and washed with ether to afford 16 g of the title compound, m.p. 220° d.

후처리

  1. temperaturewas heated on the steam bath for 30 minutes
  2. temperaturecooled
  3. filtrationfiltered
  4. washwashed with water
  5. customdried by suction
  6. washwashed with ether

출처 및 근거

ORD 기록
ord-c13829d1f13f45e4bd71f23e498d6250
출처 데이터셋
uspto-grants-1988_06
특허 번호
US04750930

반응 노트

불러오는 중…