C[C:2]([C:4]1[CH:9]=[CH:8][C:7]([F:10])=[C:6]([Cl:11])[CH:5]=1)=[O:3].Br[O-].[Na+].S([O-])(O)=[O:16].[Na+].Cl>>[Cl:11][C:6]1[CH:5]=[C:4]([CH:9]=[CH:8][C:7]=1[F:10])[C:2]([OH:3])=[O:16]The 3-chloro-4-fluoroacetophenone is then reacted with an aqueous solution of sodium hypobromite, the aqeuous phase is treated with sodium hydrogensulfite and acidified with hydrochloric acid, and the precipitated product is recrystallized from benzene. 3-Chloro-4-fluorobenzoic acid obtained in a yield of 74%.
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