[CH3:1][C:2]1[N:3]=[C:4]([NH:7][C:8]2[CH:13]=[C:12]([OH:14])[CH:11]=[CH:10][N:9]=2)[S:5][CH:6]=1.F[C:16]1[CH:23]=[CH:22][CH:21]=[CH:20][C:17]=1[C:18]#[N:19].C(=O)([O-])[O-].[K+].[K+].Cl>CS(C)=O.C1COCC1.CCOCC>[CH3:1][C:2]1[N:3]=[C:4]([NH:7][C:8]2[CH:13]=[C:12]([O:14][C:16]3[CH:23]=[CH:22][CH:21]=[CH:20][C:17]=3[C:18]#[N:19])[CH:11]=[CH:10][N:9]=2)[S:5][CH:6]=12-(4-Methylthiazol-2-ylamino)pyridin-4-ol (0.100 g, 0.483 mmol), 2-fluorobenzonitrile (0.064 g, 0.531-mmol) and potassium carbonate (0.167 g, 1.21 mmol) were combined in DMSO and heated at 90° C. overnight. The reaction mixture was partitioned between ethyl acetate and water. The organic layer was washed with water and brine, dried, and concentrated. The residue was purified by MPLC, eluting with 3:1 hexane:ethyl acetate to afford the free base. The free base was dissolved in THF (3 mL) and 1M HCl in ether (6 mL) was added. The solution was diluted with ether (15 mL), triturated for 10 minutes, and filtered to afford 2-(2-(4-methylthiazol-2-ylamino)pyridin-4-yloxy)benzonitrile (0.013 g, 8.65% yield) as white solid. 1H NMR (CDCl3) δ 8.26 (d, 1H), 7.72 (dd, 1H), 7.60 (m, 1H), 7.32 (dt, 1H), 7.14 (d, 1H), 6.53 (dd, 1H), 6.42 (d, 1H), 6.33 (d, 1H), 2.23 (d, 3H); HPLC Rt=2.67 min; Mass spectrum (esi) m/z=309 (M+H).
불러오는 중…
