Benzoic Acid → Sodium Benzoate
Reaction equation
[C:1]([OH:9])(=[O:8])[C:2]1[CH:7]=[CH:6][CH:5]=[CH:4][CH:3]=1.[OH-].[Na+:11]>CO.O>[C:1]([O-:9])(=[O:8])[C:2]1[CH:7]=[CH:6][CH:5]=[CH:4][CH:3]=1.[Na+:11]Participants
5
Reactant 2
Product 1
Reagents, catalysts & solvents 2
Procedure
50 mmol benzoic acid is dissolved in 50 mL methanol. 50 mmol NaOH dissolved in 50 mL water is added slowly to the benzoic acid solution prepared while stirring to obtain sodium benzoate. 50 mmol silver nitrate dissolved in 50 mL water is added to the sodium benzoate solution, and then white precipitate forms fast. The precipitate is silver benzoate formed by exchange of Na+ and Ag+ by ionization tendency, washed to remove unreacted silver nitrate and NaOH with water, filtered and further washed several times to remove unreacted benzoic acid with methanol, and dried at 50° C. to obtain final silver benzoate.
Workup
- customprepared
Sources & evidence
- ORD record
- ord-91e1ec46f2224e618b0aecc4ffd0e4df
- Source dataset
- uspto-grants-2011_07
- Patent number
- US07976737B2
Reaction notes
Loading…