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HRID1011979

反应详情

EQUATION

反应方程式

HRID 1011979 的结构方程式

REACTANTS

反应物

2
结构：O=Cc1ccncc1
HCID13389

Pyridin-4-carboxaldehyde

C6H5NO

结构：NNc1cccc(OC(F)(F)F)c1
HCID5194226

[3-(Trifluoromethoxy)phenyl]hydrazine

C7H7F3N2O

PRODUCTS

生成物

1
结构：FC(F)(F)Oc1cccc(N/N=C/c2ccncc2)c1
HCID87352688

未命名化合物

收率 40%

PROCEDURE

实验过程

In analogy to the procedure described in Example 167A], 3-(trifluoromethoxy)phenylhydrazine and pyridine-4-carbaldehyde gave the title compound as a light yellow solid (40%). MS: 282.0 (MH+).