Hydrochloric Acid → 4-(2-Chloroethyl)phenol
Reaction equation
[ClH:1].[OH:2][C:3]1[CH:8]=[CH:7][C:6]([CH2:9][CH2:10]O)=[CH:5][CH:4]=1>>[OH:2][C:3]1[CH:8]=[CH:7][C:6]([CH2:9][CH2:10][Cl:1])=[CH:5][CH:4]=1Participants
3
Reactant 2
Product 1
Procedure
In a similar process using 12N HCl, 2-(4-hydroxyphenyl) ethanol gave 70% isolated yield of the (2-[4-hydroxyphenyl]ethyl) chloride. 1H NMR (CDCl3) δ 2.96 (2H, t, J=7.8 Hz), 3.67 (2H, t, J=7.2 Hz), 6.79 (2H, d, J=8.4 Hz), 6.94 (2H, d, J=8.1 Hz)
Workup
- customgave 70%
Sources & evidence
- ORD record
- ord-861e1c8f4a5346bbbe38c46fe27d4e90
- Source dataset
- uspto-grants-2011_07
- Patent number
- US07985879B2
Reaction notes
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