HRID1055710

反应详情

EQUATION

反应方程式

HRID 1055710 的结构方程式

PROCEDURE

实验过程

60 mg (0.15 mmol) of the compound of Example 9A and 40 mg (0.15 mmol) of the compound of Example 25A were reacted analogously to the procedure of Example 10, except that here the reaction was stirred with trifluoroacetic acid at 80° C. only for 3 h (instead of 6 h). This gave 36 mg (43% of theory) of the title compound.