反应详情

Using the procedure described in Example 50, Part A, 2.47 g (0.01 mol) of 5-methoxy-2-methyl-1H-indole-3-acetic acid ethyl ester was reacted with 0.48 g (0.012 mol) of 60% NaH/mineral oil and then 2.17 mL (0.012 mol of iodooctane. The product was chromatographed on silica gel and eluted with 5% EtOAc/toluene to give 1.85 g (51% yield) of 5-methoxy-2-methyl-1-octyl-1H-indole-3-acetic acid ethyl ester as an oil.

1. customThe product was chromatographed on silica gel
2. washeluted with 5% EtOAc/toluene