1-Pentyn-3-ol → rac-(Z)-1,3-Dihydro-5-fluoro-4-(3-hydroxy-1-pentynyl)-3-[(1H-pyrrol-2-yl)methylene]-2H-indol-2-one
Reaction equation
[CH:1]#[C:2][CH:3]([OH:6])[CH2:4][CH3:5].[F:7][C:8]1[C:9](I)=[C:10]2[C:14](=[CH:15][CH:16]=1)[NH:13][C:12](=[O:17])/[C:11]/2=[CH:18]\[C:19]1[NH:20][CH:21]=[CH:22][CH:23]=1>C1C=CC([P]([Pd]([P](C2C=CC=CC=2)(C2C=CC=CC=2)C2C=CC=CC=2)([P](C2C=CC=CC=2)(C2C=CC=CC=2)C2C=CC=CC=2)[P](C2C=CC=CC=2)(C2C=CC=CC=2)C2C=CC=CC=2)(C2C=CC=CC=2)C2C=CC=CC=2)=CC=1.CN(C=O)C.CCN(CC)CC>[F:7][C:8]1[C:9]([C:1]#[C:2][CH:3]([OH:6])[CH2:4][CH3:5])=[C:10]2[C:14](=[CH:15][CH:16]=1)[NH:13][C:12](=[O:17])/[C:11]/2=[CH:18]\[C:19]1[NH:20][CH:21]=[CH:22][CH:23]=1Participants
6
Reactant 2
Product 1
Reagents, catalysts & solvents 3
Procedure
Using Method C above, 1-pentyn-3-ol (58.9 mg, 0.7 mmol) (Aldrich) was coupled with (Z)-1,3-dihydro-5-fluoro-4-iodo-3-[(1H-pyrrol-2-yl)methylene]-2H-indol-2-one (100 mg, 0.28 mmol) (Starting Material 5, supra) using (Ph3P)4Pd (32 mg) and Cul (5.3 mg) as catalyst in DMF (5 mL) and Et3N (5 mL) as solvent at 85° C. for 10 h to yield rac-(Z)-1,3-Dihydro-5-fluoro-4-(3-hydroxy-1-pentynyl)-3-[(1H-pyrrol-2-yl)methylene]-2H-indol-2-one. (Yield 64 mg, 70%).
Sources & evidence
- ORD record
- ord-dc00ff56086f4f7b8070adb649a79454
- Source dataset
- uspto-grants-2001_06
- Patent number
- US06252086B1
Reaction notes
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