1-Pentyn-3-ol → rac-(Z)-1,3-Dihydro-5-fluoro-4-(3-hydroxy-1-pentynyl)-3-[(1H-pyrrol-2-yl)methylene]-2H-indol-2-one

HRID 1069718Notes

Reaction equation

HRID 1069718 reaction equation
[CH:1]#[C:2][CH:3]([OH:6])[CH2:4][CH3:5].[F:7][C:8]1[C:9](I)=[C:10]2[C:14](=[CH:15][CH:16]=1)[NH:13][C:12](=[O:17])/[C:11]/2=[CH:18]\[C:19]1[NH:20][CH:21]=[CH:22][CH:23]=1>C1C=CC([P]([Pd]([P](C2C=CC=CC=2)(C2C=CC=CC=2)C2C=CC=CC=2)([P](C2C=CC=CC=2)(C2C=CC=CC=2)C2C=CC=CC=2)[P](C2C=CC=CC=2)(C2C=CC=CC=2)C2C=CC=CC=2)(C2C=CC=CC=2)C2C=CC=CC=2)=CC=1.CN(C=O)C.CCN(CC)CC>[F:7][C:8]1[C:9]([C:1]#[C:2][CH:3]([OH:6])[CH2:4][CH3:5])=[C:10]2[C:14](=[CH:15][CH:16]=1)[NH:13][C:12](=[O:17])/[C:11]/2=[CH:18]\[C:19]1[NH:20][CH:21]=[CH:22][CH:23]=1

Participants

6

Procedure

Using Method C above, 1-pentyn-3-ol (58.9 mg, 0.7 mmol) (Aldrich) was coupled with (Z)-1,3-dihydro-5-fluoro-4-iodo-3-[(1H-pyrrol-2-yl)methylene]-2H-indol-2-one (100 mg, 0.28 mmol) (Starting Material 5, supra) using (Ph3P)4Pd (32 mg) and Cul (5.3 mg) as catalyst in DMF (5 mL) and Et3N (5 mL) as solvent at 85° C. for 10 h to yield rac-(Z)-1,3-Dihydro-5-fluoro-4-(3-hydroxy-1-pentynyl)-3-[(1H-pyrrol-2-yl)methylene]-2H-indol-2-one. (Yield 64 mg, 70%).

Sources & evidence

ORD record
ord-dc00ff56086f4f7b8070adb649a79454
Source dataset
uspto-grants-2001_06
Patent number
US06252086B1

Reaction notes

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