Tetrahydrofuran → HCID 12218047, compound
Reaction equation
[OH-].[K+].[O:3]=[C:4]([CH:8]([C:10]1[CH:15]=[CH:14][CH:13]=[CH:12][CH:11]=1)[CH3:9])[C:5]([OH:7])=[O:6].O1CCC[CH2:17]1>>[O:3]=[C:4]([C:8]([CH3:17])([C:10]1[CH:15]=[CH:14][CH:13]=[CH:12][CH:11]=1)[CH3:9])[C:5]([OH:7])=[O:6]Participants
4
Procedure
Example 14 was repeated except that 4.0 ml (9.0 mmoles) of a 2.25N aqueous solution of potassium hydroxide was used instead of lithium hydroxide as a base, and 8 ml of tetrahydrofuran was used as a solvent. A mixture of 2-oxo-3-phenylbutanoic acid (65 %) and 2-oxo-3-methyl-3-phenylbutanoic acid (11 %) was obtained.
Sources & evidence
- ORD record
- ord-f9e52d5aa848434d9d29fbb3b264dcf2
- Source dataset
- uspto-grants-1991_07
- Patent number
- US05028738
Reaction notes
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