Ethyl Acetate → 4-Methylfluorene
Reaction equation
O[CH:2]1[C:14]2[CH:13]=[CH:12][CH:11]=[C:10]([CH2:15]O)[C:9]=2[C:8]2[C:3]1=[CH:4][CH:5]=[CH:6][CH:7]=2.CCOC(C)=O.[H][H]>[Pd].CC(O)=O>[CH3:15][C:10]1[C:9]2[C:8]3[C:3](=[CH:4][CH:5]=[CH:6][CH:7]=3)[CH2:2][C:14]=2[CH:13]=[CH:12][CH:11]=1Participants
6
Reactant 3
Product 1
Reagents, catalysts & solvents 2
Procedure
A solution of 9-hydroxyfluoren-4-methanol (2.6 g, 12.2 mmol) in 1.1 EtOAc:AcOH was charged with catalytic amount of 10% palladium on charcoal. The mixture was treated with hydrogen under 1600 psi, at room temperature for three days. The catalyst was removed and the solvent was evaporated under reduced pressure. Recrystalyzation from MeOH afforded 1.7 g (77.0%) of the product as a light yellow solid.
Workup
- customThe catalyst was removed
- customthe solvent was evaporated under reduced pressure
Sources & evidence
- ORD record
- ord-b24e7e79fc1b4f088fdc4c3c513258a6
- Source dataset
- uspto-grants-1992_01
- Patent number
- US05079260
Reaction notes
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