Lithium diisopropylamide → HCID 15035374, compound

HRID 1090273Notes

Reaction equation

HRID 1090273 reaction equation
[Cl:1][C:2]1[CH:33]=[CH:32][C:5]([CH2:6][N:7]2[C:15]3[C:10](=[CH:11][C:12]([CH:16]([CH3:18])[CH3:17])=[CH:13][CH:14]=3)[C:9]([S:19][C:20]3[CH:25]=[CH:24][CH:23]=[CH:22][CH:21]=3)=[C:8]2[CH2:26][C:27]([O:29][CH2:30][CH3:31])=[O:28])=[CH:4][CH:3]=1.[CH:34]([N-]C(C)C)(C)C.[Li+]>O1CCCC1>[Cl:1][C:2]1[CH:3]=[CH:4][C:5]([CH2:6][N:7]2[C:15]3[C:10](=[CH:11][C:12]([CH:16]([CH3:17])[CH3:18])=[CH:13][CH:14]=3)[C:9]([S:19][C:20]3[CH:25]=[CH:24][CH:23]=[CH:22][CH:21]=3)=[C:8]2[CH:26]([CH3:34])[C:27]([O:29][CH2:30][CH3:31])=[O:28])=[CH:32][CH:33]=1

Participants

4

Reactant 2

HCID 2724682Lithium diisopropylamideHCID 15035372HCID 15035372, compound

Product 1

HCID 15035374HCID 15035374, compound

Reagents, catalysts & solvents 1

HCID 8028TetrahydrofuranSolvent

Procedure

Following the procedure of Example 6, Step 1, but using ethyl 1-(p-chlorobenzyl)-3-phenylthio -5-(i-propyl)-indole-2-acetate (Example 10, Step 1) as the starting material, lithium diisopropylamide as base, and tetrahydrofuran as solvent, ethyl 1-(p-chlorobenzyl)-α-methyl-3-phenylthio-5-(i-propyl)-indole-2-acetate was prepared.

Sources & evidence

ORD record
ord-a330e700657d418eb1c2fd3314099eaa
Source dataset
uspto-grants-1992_01
Patent number
US05081138

Reaction notes

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