Tetrafluoroboric acid → Iodonium, diphenyl-, hexafluorophosphate(1-) (1:1)

HRID 1105790Notes

Reaction equation

[Cl-].[C:2]1([I+:8][C:9]2[CH:14]=[CH:13][CH:12]=[CH:11][CH:10]=2)[CH:7]=[CH:6][CH:5]=[CH:4][CH:3]=1.F[B-](F)(F)F.[H+].[F:21][P-:22]([F:27])([F:26])([F:25])([F:24])[F:23].[H+]>>[F:21][P-:22]([F:27])([F:26])([F:25])([F:24])[F:23].[C:9]1([I+:8][C:2]2[CH:3]=[CH:4][CH:5]=[CH:6][CH:7]=2)[CH:10]=[CH:11][CH:12]=[CH:13][CH:14]=1

Participants

Reactant 3

HCID 28118Tetrafluoroboric acid

HCID 73870Diphenyliodonium chloride

HCID 16211447Hexafluorophosphoric acid

Product 1

HCID 2737136Iodonium, diphenyl-, hexafluorophosphate(1-) (1:1)Yield 74%

Procedure

The procedure of Example 1 was repeated for preparing an aromatic halonium salt using diphenyliodonium chloride. In this preparation, fluoroboric acid was replaced by 25 ml (60%) hexafluorophosphoric acid. There was obtained a 74% yield of diphenyliodonium hexafluorophosphate having a m.p. of 139°-141° C.

Sources & evidence

ORD record: ord-48642f58e3b84aca8818938e77021646
Source dataset: uspto-grants-1982_01
DOI: 10.6084/m9.figshare.5104873.v1
Patent number: US04310469

Reaction notes

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