(Phenylmethoxy)acetaldehyde → 2-(Benzyloxy) ethanol
Reaction equation
C(=O)([O-])O.[Na+].[CH2:6]([O:13][CH2:14][CH:15]=[O:16])[C:7]1[CH:12]=[CH:11][CH:10]=[CH:9][CH:8]=1>>[CH2:6]([O:13][CH2:14][CH:15]=[O:16])[C:7]1[CH:12]=[CH:11][CH:10]=[CH:9][CH:8]=1.[CH2:6]([O:13][CH2:14][CH2:15][OH:16])[C:7]1[CH:12]=[CH:11][CH:10]=[CH:9][CH:8]=1Participants
4
Procedure
Example 1 was repeated except that 2.5 g (30 mmoles) of sodium hydrogen carbonate was used instead of 2.6 g (15 mmoles ) of dipotassium hydrogen phosphate, to obtain 7.1 g of benzyloxyacetaldehyde and 4.5 g of 2-benzyloxyethanol (yield of benzyloxyacetaldehyde based on the 2-benzyloxyethanol that had reacted: 66.8%, ratio of recovery of 2-benzyloxyethanol: 29.6%).
Sources & evidence
- ORD record
- ord-016bf7d79d9742119113d1bb520a0dce
- Source dataset
- uspto-grants-2003_09
- Patent number
- US06624331B1
Reaction notes
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