Hydrochloric Acid → 4-(Morpholin-4-yl)benzoic acid
Reaction equation
[Li+].[OH-].C[O:4][C:5](=[O:18])[C:6]1[CH:11]=[CH:10][C:9]([N:12]2[CH2:17][CH2:16][O:15][CH2:14][CH2:13]2)=[CH:8][CH:7]=1.O.Cl>C1COCC1.O>[N:12]1([C:9]2[CH:8]=[CH:7][C:6]([C:5]([OH:18])=[O:4])=[CH:11][CH:10]=2)[CH2:13][CH2:14][O:15][CH2:16][CH2:17]1Participants
6
Reactant 4
Product 1
Reagents, catalysts & solvents 1
Procedure
LiOH (92 mg, 0.22 mmol) was added to a stirred solution of 4-morpholin-4-yl-benzoic acid methyl ester (162 mg, 0.73 mmol) in THF:H2O (1:1, 4 mL), and the resulting mixture was stirred at room temperature for 20 hrs. The reaction mixture was concentrated under reduced pressure to get the residue. Cold water was then added and acidified it with 10% aqueous HCl, filtered the solid precipitated to afford 130 mg (86% yield) of 4-morpholin-4-yl-benzoic acid. 1H NMR (DMSO-d6): δ 12.4 (s, 1H), 7.8 (d, 2H), 7.0 (d, 2H), 3.76 (t, 4H), 3.28 (t, 4H).
Workup
- concentrationThe reaction mixture was concentrated under reduced pressure
- customto get the residue
- filtrationfiltered the solid
- customprecipitated
Sources & evidence
- ORD record
- ord-da30a61e5ec542ec9756409eebb00874
- Source dataset
- uspto-grants-2010_11
- Patent number
- US07842696B2
Reaction notes
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