Lithium Hydroxide → HCID 58978928, compound

HRID 1180562Notes

Reaction equation

HRID 1180562 reaction equation
[C:1]([N:9]1[C:15]2[CH:16]=[CH:17][CH:18]=[CH:19][C:14]=2[CH2:13][N:12]([S:20]([C:23]2[CH:28]=[CH:27][C:26]([O:29][CH2:30][CH:31]=[C:32]=[CH:33][CH3:34])=[CH:25][CH:24]=2)(=[O:22])=[O:21])[CH:11]([C:35]([O:37]C)=[O:36])[CH2:10]1)(=[O:8])[C:2]1[CH:7]=[CH:6][CH:5]=[CH:4][CH:3]=1.[OH-].[Li+]>O.CO.O1CCCC1>[C:1]([N:9]1[C:15]2[CH:16]=[CH:17][CH:18]=[CH:19][C:14]=2[CH2:13][N:12]([S:20]([C:23]2[CH:24]=[CH:25][C:26]([O:29][CH2:30][CH:31]=[C:32]=[CH:33][CH3:34])=[CH:27][CH:28]=2)(=[O:22])=[O:21])[CH:11]([C:35]([OH:37])=[O:36])[CH2:10]1)(=[O:8])[C:2]1[CH:3]=[CH:4][CH:5]=[CH:6][CH:7]=1

Participants

6

Reactant 2

HCID 3939Lithium HydroxideHCID 58978916HCID 58978916, compound

Product 1

HCID 58978928HCID 58978928, compoundYield 95.3%

Reagents, catalysts & solvents 3

HCID 887MethanolSolventHCID 962WaterSolventHCID 8028TetrahydrofuranSolvent

Procedure

The procedure of Example 42 was followed using the product from Example 41 (280 mg, 0.526 mmol), lithium hydroxide (55 mg, 1.32 mmol) in water (0.4 ml), methanol (1 ml) and tetrahydrofuran (1 ml) to give 260 mg (95%) of the product.

Sources & evidence

ORD record
ord-6e22d8f2ffdd425cb0cca6b120e011a0
Source dataset
uspto-grants-2007_10
Patent number
US07282496B2

Reaction notes

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