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HRID1196925

反应详情

EQUATION

反应方程式

HRID 1196925 的结构方程式

REACTANTS

反应物

4
结构：CCOCC
HCID3283

Diethyl Ether

C4H10O

结构：O=C(Cn1cncn1)c1ccc(F)cc1F
HCID588080

2,4-Difluoro-alpha-(1H-1,2,4-triazolyl)acetophenone

C10H7F2N3O

结构：CC(C)[N-]C(C)C.[Li+]
HCID2724682

2-Propanamine, N-(1-methylethyl)-, lithium salt

C6H14LiN

结构：CC(C)c1ccncn1
HCID18956506

未命名化合物

PRODUCTS

生成物

1
结构：CC(C)(c1ccncn1)C(O)(Cn1cncn1)c1ccc(F)cc1F
HCID18956517

未命名化合物

收率 2.7%

AUXILIARIES

试剂、催化剂与溶剂

1
结构：C1CCOC1
溶剂HCID8028

Tetrahydrofuran

C4H8O

PROCEDURE

实验过程

Treatment of the product of part (i) (2.46 g) with lithium diisopropylamide (0.02 mole) in dry tetrahydrofuran followed by 1-(2,4-difluorophenyl)-2-(1H-1,2,4-triazol-1-yl)ethanone (4.49 g) according to the method of Example 3 gave the title compound, (0.185 g), m.p. 126°-127° (from ether).