Water → 4-Fluoro-3-nitrobenzaldehyde

HRID 1263345Notes

Reaction equation

HRID 1263345 reaction equation
Cl[C:2]1[CH:9]=[CH:8][C:5]([CH:6]=[O:7])=[CH:4][C:3]=1[N+:10]([O-:12])=[O:11].[F-:13].[K+].O>S1(CCCC1)(=O)=O>[F:13][C:2]1[CH:9]=[CH:8][C:5]([CH:6]=[O:7])=[CH:4][C:3]=1[N+:10]([O-:12])=[O:11]

Participants

5

Reactant 3

HCID 962WaterHCID 855054-Chloro-3-nitrobenzaldehydeHCID 522689Potassium Fluoride

Product 1

HCID 5981294-Fluoro-3-nitrobenzaldehydeYield 92.5%

Reagents, catalysts & solvents 1

HCID 31347SulfolaneSolvent

Procedure

18.6 g (0.1 mol) of 4-chloro-3-nitrobenzaldehyde and 8.7 g (0.15 mol) of potassium fluoride in 100 ml of sulpholane are stirred for 1 hour at 180° C. The mixture is stirred with 300 ml of water and the aldehyde is extracted with methylene chloride. After the customary working-up , 17.1 g of 92% strength 4-fluoro-3-nitrobenzaldehyde are obtained.

Workup

  1. extractionthe aldehyde is extracted with methylene chloride

Sources & evidence

ORD record
ord-f071ae876cf041d5913356dd0bba083a
Source dataset
uspto-grants-1984_06
Patent number
US04456772

Reaction notes

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