Hydrogen Bromide → 4-Methylisoquinolin-7-ol
Reaction equation
C[O:2][C:3]1[CH:12]=[C:11]2[C:6]([C:7]([CH3:13])=[CH:8][N:9]=[CH:10]2)=[CH:5][CH:4]=1.Br>>[OH:2][C:3]1[CH:12]=[C:11]2[C:6]([C:7]([CH3:13])=[CH:8][N:9]=[CH:10]2)=[CH:5][CH:4]=1Participants
3
Procedure
A mixture of 17.3 g. (0.1 mole) of 7-methoxy-4-methylisoquinoline and 100 ml. of 48% hydrobromic acid is refluxed for sixteen hours and evaporated in vacuo. The residue is dissolved in water, neutralized with ammonium hydroxide and filtered to yield 7-hydroxy-4-methylisoquinoline.
Workup
- additionA mixture of 17.3 g
- customevaporated in vacuo
- dissolutionThe residue is dissolved in water
- filtrationfiltered
Sources & evidence
- ORD record
- ord-948ffba10f3c482688859b302143d3f1
- Source dataset
- uspto-grants-1981_03
- Patent number
- US04258049
Reaction notes
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