HRID1357624

反应详情

EQUATION

反应方程式

HRID 1357624 的结构方程式

PROCEDURE

实验过程

The title compound was prepared according to the procedure of example 50, step 2, starting from the product obtained in step 1 above (1.62 g, 4.96 mmol), piperazine (1.28 g, 14.9 mmol) and K2CO3 (0.70 g, 5.1 mmol). The yield of the title compound was 1.16 g (62%) and was obtained as an oil. HRMS m/z calcd for C22H24N4O2 (M)+ 376.1899, found 376.1890. Anal. (C22H24N4O2) C, H, N.

WORKUP

后处理

  1. customThe title compound was prepared
  2. customwas obtained as an oil