Potassium Iodide → HCID 14422897, compound

HRID 1382404Notes

Reaction equation

HRID 1382404 reaction equation
[Cl:1][CH2:2][CH2:3][CH:4]([OH:15])[CH2:5][O:6][C:7]1[CH:12]=[CH:11][C:10]([Cl:13])=[C:9]([Cl:14])[CH:8]=1.[C:16]1([N:22]2[CH2:27][CH2:26][NH:25][CH2:24][CH2:23]2)[CH:21]=[CH:20][CH:19]=[CH:18][CH:17]=1.C(=O)([O-])[O-].[Na+].[Na+].[I-].[K+]>Cl.C(O)CCC>[ClH:1].[ClH:1].[Cl:14][C:9]1[CH:8]=[C:7]([CH:12]=[CH:11][C:10]=1[Cl:13])[O:6][CH2:5][CH:4]([OH:15])[CH2:3][CH2:2][N:25]1[CH2:26][CH2:27][N:22]([C:16]2[CH:21]=[CH:20][CH:19]=[CH:18][CH:17]=2)[CH2:23][CH2:24]1

Participants

7

Reactant 4

HCID 4875Potassium IodideHCID 70961-PhenylpiperazineHCID 10340Sodium CarbonateHCID 14422833HCID 14422833, compound

Product 1

HCID 14422897HCID 14422897, compound

Reagents, catalysts & solvents 2

HCID 2631-ButanolSolventHCID 313Hydrochloric AcidSolvent

Procedure

This compound was prepared according to the procedure of Example 97. A mixture of 8.1 g (0.03 mole) of 4-chloro-1-(3,4-dichlorophenoxy)-2-butanol, 4.9 g (0.03 mole) of 1-phenylpiperazine, 16.0 g (0.15 mole) of anhydrous sodium carbonate and 0.3 g (0.002 mole) of potassium iodide in a total volume of 200 ml of 1-butanol gave a golden oil as residue. The hydrochloric acid salt was formed in ethereal hydrogen chloride and the collected solid was recrystallized from methanol-ethyl ether to give 5.1 g (37%) of white solid, m.p. 210°-213° C.

Workup

  1. customThis compound was prepared
  2. customgave a golden oil as residue

Sources & evidence

ORD record
ord-9bb6aafcb1f44d7ab587c5832491de87
Source dataset
uspto-grants-1989_02
Patent number
US04806555

Reaction notes

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