Potassium Iodide → Hydrochloric Acid
Reaction equation
[CH3:1][C:2]1[CH:7]=[CH:6][C:5]([N:8]2[CH2:13][CH2:12][NH:11][CH2:10][CH2:9]2)=[CH:4][CH:3]=1.[Cl:14][CH2:15][CH2:16][CH:17]([OH:27])[CH2:18][O:19][C:20]1[CH:25]=[CH:24][C:23]([Cl:26])=[CH:22][CH:21]=1.C(=O)([O-])[O-:29].[Na+].[Na+].[I-].[K+]>CC(O)C.C(O)CCC>[OH2:19].[ClH:14].[Cl:26][C:23]1[CH:24]=[CH:25][C:20]([O:19][CH2:18][CH:17]([OH:27])[CH2:16][CH2:15][N:11]2[CH2:12][CH2:13][N:8]([C:5]3[CH:4]=[CH:3][C:2]([CH3:1])=[CH:7][CH:6]=3)[CH2:9][CH2:10]2)=[CH:21][CH:22]=1.[OH2:29].[OH2:19].[Cl:26][C:23]1[CH:24]=[CH:25][C:20]([O:19][CH2:18][CH:17]([OH:27])[CH2:16][CH2:15][N:11]2[CH2:12][CH2:13][N:8]([C:5]3[CH:4]=[CH:3][C:2]([CH3:1])=[CH:7][CH:6]=3)[CH2:9][CH2:10]2)=[CH:21][CH:22]=1.[ClH:14].[ClH:14]Participants
8
Procedure
This compound was prepared according to the procedure of Example 97. A mixture of 1.8 g (0.01 mole) of 1-(4-methylphenyl)piperazine, 2.4 g (0.01 mole) of 4-chloro-1-(4-chlorophenoxy)-2-butanol, 5.2 g (0.05 mole) of anhydrous sodium carbonate and 0.1 g of potassium iodide in a total volume of 200 ml of 1-butanol gave a golden oil as residue. The hydrochloride was formed in 2-propanol saturated with hydrogen chloride and the collected solid was recrystallized from ethanol-water-ethyl ether to give 1.4 g (31%) of white solid, m.p. 190°-195° C.
Workup
- customThis compound was prepared
- customgave a golden oil as residue
Sources & evidence
- ORD record
- ord-6a7b290c67f749a1bda5046156130165
- Source dataset
- uspto-grants-1989_02
- Patent number
- US04806555
Reaction notes
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