Potassium Iodide → Hydrochloric Acid

HRID 1382417Notes

Reaction equation

HRID 1382417 reaction equation
[CH3:1][O:2][C:3]1[CH:8]=[CH:7][C:6]([N:9]2[CH2:14][CH2:13][NH:12][CH2:11][CH2:10]2)=[CH:5][CH:4]=1.[Cl:15][CH2:16][CH2:17][CH:18]([OH:28])[CH2:19][O:20][C:21]1[CH:26]=[CH:25][C:24]([Cl:27])=[CH:23][CH:22]=1.C(=O)([O-])[O-].[Na+].[Na+].[I-].[K+]>CC(O)C.C(O)CCC>[ClH:15].[ClH:15].[Cl:27][C:24]1[CH:25]=[CH:26][C:21]([O:20][CH2:19][CH:18]([OH:28])[CH2:17][CH2:16][N:12]2[CH2:13][CH2:14][N:9]([C:6]3[CH:5]=[CH:4][C:3]([O:2][CH3:1])=[CH:8][CH:7]=3)[CH2:10][CH2:11]2)=[CH:22][CH:23]=1.[ClH:15]

Participants

8

Reactant 4

HCID 4875Potassium IodideHCID 10340Sodium CarbonateHCID 2697221-(4-Methoxyphenyl)piperazineHCID 131203494-Chloro-1-(4-chlorophenoxy)-2-butanol

Product 2

HCID 313Hydrochloric AcidHCID 14422870HCID 14422870, compound

Reagents, catalysts & solvents 2

HCID 2631-ButanolSolventHCID 3776IsopropanolSolvent

Procedure

This compound was prepared according to the procedure of Example 97. A mixture of 3.0 g (0.015 mole) of 1-(4-methoxyphenyl)-piperazine, 3.7 g (0.015 mole) of 4-chloro-1-(4-chlorophenoxy)-2-butanol, 5.2 g (0.05 mole) of anhydrous sodium carbonate and 0.1 g of potassium iodide in a total volume of 200 ml of 1-butanol gave an oil as residue. The hydrochloride was formed in 2-propanol saturated with hydrogen chloride and the collected solid was recrystallized from methanol-water to give 3.3 g (42%) of white, crystalline solid, m.p. 220°-225° C.

Workup

  1. customThis compound was prepared
  2. customgave an oil as residue

Sources & evidence

ORD record
ord-0cf1566918b445e0995e20e669b03039
Source dataset
uspto-grants-1989_02
Patent number
US04806555

Reaction notes

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