Dimethylformamide → Methyl 3-Methoxy-2-naphthoate
Reaction equation
[OH:1][C:2]1[C:3]([C:12]([OH:14])=O)=[CH:4][C:5]2[C:10]([CH:11]=1)=[CH:9][CH:8]=[CH:7][CH:6]=2.CI.[C:17](=O)([O-])[O-].[K+].[K+].CN(C)[CH:25]=[O:26]>O>[CH3:17][O:1][C:2]1[C:3]([C:12]([O:26][CH3:25])=[O:14])=[CH:4][C:5]2[C:10]([CH:11]=1)=[CH:9][CH:8]=[CH:7][CH:6]=2Participants
6
Reactant 4
Product 1
Reagents, catalysts & solvents 1
Procedure
A mixture of 18.8 g. (0.1 mole) of 3-hydroxy-2-naphthoic acid, 20 ml. of methyl iodide, 28 g. of potassium carbonate, and 200 ml. of N,N-dimethylformamide was heated at 70° C. for 16 hours, then poured into 1 liter of water. The mixture was extracted with diethyl ether and the extracts were washed with water, then 5 percent sodium hydroxide solution, then water again, and dried over magnesium sulfate. Evaporation provided a residue of methyl 3-methoxy-2-naphthoate.
Workup
- additionA mixture of 18.8 g
- extractionThe mixture was extracted with diethyl ether
- washthe extracts were washed with water
- dry with material5 percent sodium hydroxide solution, then water again, and dried over magnesium sulfate
- customEvaporation
Sources & evidence
- ORD record
- ord-2660ec040ce8472c964963172aa358d4
- Source dataset
- uspto-grants-1984_02
- Patent number
- US04432986
Reaction notes
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